<div dir="ltr">I don't know if one less iteration will make much difference, however I also agree the each+31 case should be the last one.</div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">El mié., 9 oct. 2019 a las 0:11, Andres Valloud via Cuis-dev (<<a href="mailto:cuis-dev@lists.cuis.st" target="_blank">cuis-dev@lists.cuis.st</a>>) escribió:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex">Regarding each+31, sure, 30*k+1 comes first, except when k = 0 because <br>
why would anyone try dividing by 1. So this is why that case is shifted <br>
by 30. However, when written this way, the actual divisor evaluation <br>
order is 31, 7, 11, and so on. It's more likely that a random integer <br>
is 0 mod 7 than 0 mod 31, and the sooner one detects exact division, the <br>
sooner the computation can stop. Because of that, I think the each+31 <br>
case should be the last one in the division loop.<br>
<br>
On 10/8/19 19:17, Agustín Sansone via Cuis-dev wrote:<br>
> Hello!<br>
> <br>
> I agree with you. I don't think isPrime should send isProbablyPrime <br>
> because it could fail in the future.<br>
> I leave you here the implementation with this taken care of.<br>
> I wrote the (each+31) case first in the trial division loop, because it <br>
> is testing the 30*k+1 case, wich I also wrote first in the comment.<br>
> <br>
> Thanks,<br>
> Agustín<br>
> <br>
> El mar., 8 oct. 2019 a las 8:11, Juan Vuletich via Cuis-dev <br>
> (<<a href="mailto:cuis-dev@lists.cuis.st" target="_blank">cuis-dev@lists.cuis.st</a> <mailto:<a href="mailto:cuis-dev@lists.cuis.st" target="_blank">cuis-dev@lists.cuis.st</a>>>) escribió:<br>
> <br>
> Hi Folks,<br>
> <br>
> I agree with Andrés comments, and will just focusing on the proposed<br>
> changes.<br>
> (snip)<br>
> <br>
> On 10/8/2019 2:20 AM, Andres Valloud via Cuis-dev wrote:<br>
> > Agustin, nice to see someone looking into these kinds of things :).<br>
> > ...<br>
> >> * The *raisedToInteger: exp modulo: m *method**in Integer has<br>
> a very<br>
> >> big problem. If we compute, for example, /"5 raisedTo: 0 modulo:<br>
> >> 0"/, this returns 1. This means, that according to<br>
> Smalltalk, the<br>
> >> rest of the division by 0 of 1(=5^0) is equal to 1 (Yes,<br>
> division by<br>
> >> zero!!). I think you can see the problem. This is due the<br>
> first line<br>
> >> of the method, that says /"(exp = 0) ifTrue: [^ 1].", /does<br>
> >> not check anything else. This problem can be easily fixed by<br>
> >> checking if m=0 just before.<br>
> ><br>
> > I agree, the current code appears to be wrong. The initials on the<br>
> > code belong to Juan Vuletich and Nicolas Cellier. Guys, is there<br>
> > reason why e.g. 5 raisedTo: 0 modulo: 0 should answer 1 rather than<br>
> > fail? I don't see any, but...<br>
> ><br>
> > Assuming the code is broken and needs to be fixed, alternatively one<br>
> > could also write the initial guard clause like this:<br>
> ><br>
> > n = 0 ifTrue: [^1 \\ m].<br>
> ><br>
> > because the case m = 0 will fail.<br>
> > ...<br>
> <br>
> Just added this suggestion as an update to GitHub. Andrés, I did it<br>
> with<br>
> your author initials, it's your code!<br>
> <br>
> > ...<br>
> >> * The *isPrime *method in Integer makes some optimization in<br>
> order to<br>
> >> run the algorithm in O(sqrt(self)) instead of the naive way in<br>
> >> O(self). This is very intelligent, but the constant factor<br>
> of this<br>
> >> method can be still improved significantly. I share with you my<br>
> >> implementation of *isPrimeFast *with a small explanation. This<br>
> >> implementation runs in general more than 3 times faster than the<br>
> >> actual one. I leave you a test that checks the correctness<br>
> of it as<br>
> >> well, and some other tests that check this complexity I<br>
> mentioned.<br>
> ><br>
> > I see what you did there, but I do not know how to reproduce the<br>
> time<br>
> > tests you mention. I built a sample of integers between 1 and<br>
> 2^32 (I<br>
> > didn't go up to 2^64 because that would require O(2^32) operations<br>
> > each, and I want that to finish in reasonable time), and I get<br>
> > something like a 2x performance improvement rather than 3x. This<br>
> > seems to make sense because the approach you propose halves the \\<br>
> > operations (8 remain out of the 16 the current code is doing, for<br>
> > every batch of 30 potential divisors).<br>
> ><br>
> > slicer := 1024.<br>
> > thickness := 255.<br>
> > maxK := 1 bitShift: 32.<br>
> > integers := 1 to: maxK by: maxK // slicer<br>
> > :: inject: OrderedCollection new<br>
> > into: [:t :x |<br>
> > t add: x.<br>
> > thickness timesRepeat: [t add: t last + 1].<br>
> > t yourself]<br>
> > :: asArray.<br>
> > Time millisecondsToRun:<br>
> > [1 to: integers size do:<br>
> > [:x | (integers at: x) isPrime]]<br>
> ><br>
> > Using the above code (which I could not format more nicely in this<br>
> > email), I get about 4.8s for isPrime, and about 2.4s for isPrimeFast.<br>
> ><br>
> > Generally, isPrime shouldn't send isProbablyPrime because isPrime is<br>
> > meant to be deterministic, and one shouldn't assume that the<br>
> > probabilistic algorithm today will happen to provide the correct<br>
> > deterministic answer tomorrow.<br>
> ><br>
> > Why is the (each+31) case first in the trial division loop?<br>
> ><br>
> > Andres.<br>
> <br>
> I'll wait for your consensus on what to do here. Making isPrime not<br>
> send<br>
> isProbablyPrime sounds reasonable to me, but folks, I prefer to wait<br>
> for<br>
> your suggestion.<br>
> <br>
> Thanks,<br>
> <br>
> -- <br>
> Juan Vuletich<br>
> <a href="http://www.cuis-smalltalk.org" rel="noreferrer" target="_blank">www.cuis-smalltalk.org</a> <<a href="http://www.cuis-smalltalk.org" rel="noreferrer" target="_blank">http://www.cuis-smalltalk.org</a>><br>
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> @JuanVuletich<br>
> <br>
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